X^2-2x/x^2-3x-4

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Solution for X^2-2x/x^2-3x-4 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

X^2-(3*x)-((2*x)/(x^2))-4 = 0

X^2-3*x-2*x^-1-4 = 0

-3*x^1-2*x^-1-4*x^0 = 0

(-3*x^2-4*x^1-2*x^0)/(x^1) = 0 // * x^2

x^1*(-3*x^2-4*x^1-2*x^0) = 0

x^1

-3*x^2-4*x-2 = 0

-3*x^2-4*x-2 = 0

DELTA = (-4)^2-(-3*(-2)*4)

DELTA = -8

DELTA < 0

x in { } 

x belongs to the empty set

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